Me Starting Up A Puzzle Game: Heehee Hoohoo Fuck Yes I Love Puzzle

jimi hendrix reacts to... his cheesecak...

Return of Parkciv text posts! (With bonus memes)

I am not fucking immune to seeing my blorbos in my everything. I never create these with the intention of them being Seawatt-centric it just... happens

You can find the first one I made here

there is no excuse to not know anything about everything

I came up with this three-way table to help me (and now you, if you want) to rate things out of 5 stars. I was thinking of books and films when I made it, but you can probably use it for other stuff.

The idea is that you rate the thing on how much stuff you loved and how much stuff you hated, and those things weight against each other. There's only one way to get 5 stars or 1 star, so those should end up as the rarest ratings, wtih 3 stars being the most common.

'Spicy' means that the thing inspires emotion, whether positive or negative, while 'bland' means it doesn't affect you much either way.

An example of a 3-star (spicy) - for me personally - would be the Twilight series, because there's plenty of garbage in there but also some things that are like crack to me. I can't think of an example of a 3 star (bland) because by nature they don't stick in the mind.

(This also assumes giving 0 stars isn't allowed. That'd throw it out of whack...)

P(A)=Number of favorable outcomesTotal number of possible outcomesP(A) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}P(A)=Total number of possible outcomesNumber of favorable outcomes​

P(A′)=1−P(A)P(A') = 1 - P(A)P(A′)=1−P(A)

P(A∪B)=P(A)+P(B)P(A \cup B) = P(A) + P(B)P(A∪B)=P(A)+P(B)

P(A∪B)=P(A)+P(B)−P(A∩B)P(A \cup B) = P(A) + P(B) - P(A \cap B)P(A∪B)=P(A)+P(B)−P(A∩B)

P(A∣B)=P(A∩B)P(B)P(A | B) = \frac{P(A \cap B)}{P(B)}P(A∣B)=P(B)P(A∩B)​

P(A∩B)=P(A)⋅P(B)P(A \cap B) = P(A) \cdot P(B)P(A∩B)=P(A)⋅P(B)

P(A∩B)=P(A)⋅P(B∣A)P(A \cap B) = P(A) \cdot P(B | A)P(A∩B)=P(A)⋅P(B∣A)

P(A∣B)=P(B∣A)⋅P(A)P(B)P(A | B) = \frac{P(B | A) \cdot P(A)}{P(B)}P(A∣B)=P(B)P(B∣A)⋅P(A)​

P(A)=∑i=1nP(A∣Bi)⋅P(Bi)P(A) = \sum_{i=1}^{n} P(A | B_i) \cdot P(B_i)P(A)=∑i=1n​P(A∣Bi​)⋅P(Bi​)

p(x)p(x)p(x): E(X)=∑xx⋅p(x)E(X) = \sum_{x} x \cdot p(x)E(X)=∑x​x⋅p(x)

Var(X)=E(X2)−[E(X)]2\text{Var}(X) = E(X^2) - [E(X)]^2Var(X)=E(X2)−[E(X)]2

σX=Var(X)\sigma_X = \sqrt{\text{Var}(X)}σX​=Var(X)​

P(X=k)=(nk)pk(1−p)n−kP(X = k) = \binom{n}{k} p^k (1-p)^{n-k}P(X=k)=(kn​)pk(1−p)n−k where (nk)=n!k!(n−k)!\binom{n}{k} = \frac{n!}{k!(n-k)!}(kn​)=k!(n−k)!n!​

P(X=k)=λke−λk!P(X = k) = \frac{\lambda^k e^{-\lambda}}{k!}P(X=k)=k!λke−λ​

f(x)=1σ2πe−(x−μ)22σ2f(x) = \frac{1}{\sigma \sqrt{2\pi}} e^{-\frac{(x-\mu)^2}{2\sigma^2}}f(x)=σ2π​1​e−2σ2(x−μ)2​

Hi I only dare to ask on anon, but why are you so awesome?

You forgot to turn on anon.

I think flat chested girls are going to super heaven and having 1000000 years of good luck and love

When I was but a wee baby high schooler I made this on my school issued chromebook and posted it to my og tumblr blog and I just knew in my heart it would do numbers but alas it got 1 note. (me on my other blog)